If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1.5x^2-40x-73.5=0
a = 1.5; b = -40; c = -73.5;
Δ = b2-4ac
Δ = -402-4·1.5·(-73.5)
Δ = 2041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-\sqrt{2041}}{2*1.5}=\frac{40-\sqrt{2041}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+\sqrt{2041}}{2*1.5}=\frac{40+\sqrt{2041}}{3} $
| 14-8x=-2(-3x+7) | | g/6=3 | | 7x=10(x-3) | | 5.6x-7.7=20/3x+12 | | 3=12/3x | | -33=n-17 | | 6(x-8)(7)=x-3 | | .−3=h+8÷2 | | 5.6x-7.7=62/3x+12 | | 12y+30=84 | | 2/3(3x+9)=4(x-15) | | 5x-9=2x/6 | | -30=x/4-(-14) | | 1/4(40-8x)=19x+12-5x | | 8x-8-2x=-(x+50) | | -2k=-k−6 | | 7(x-3)=x | | -5(2x+2)=10(1-x) | | x+5(-1)=2 | | 4=(3/4m)-6 | | 2+4(x-1)22;x=6 | | 6(x-8)=x | | 5(3m-6)=30 | | 3/4(y+6)=12 | | 5=-19+c | | ⅗(x+¾)+0.15=6 | | 4x-1=6x=3 | | 4y-8=92 | | -9(k+6)=-207 | | 40+14j=2(-4j-1) | | n=36+16/2 | | 8+22=-5+3x-6 |